0.55=0.45a^2

Solution for 0.55=0.45a^2 equation:

0.55=0.45a^2

We move all terms to the left:

0.55-(0.45a^2)=0

We get rid of parentheses

-0.45a^2+0.55=0

a = -0.45; b = 0; c = +0.55;
Δ = b2-4ac
Δ = 02-4·(-0.45)·0.55
Δ = 0.99
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.99}}{2*-0.45}=\frac{0-\sqrt{0.99}}{-0.9}
=-\frac{\sqrt{}}{-0.9}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.99}}{2*-0.45}=\frac{0+\sqrt{0.99}}{-0.9}
=\frac{\sqrt{}}{-0.9}
$